3(x+2)(x-2)=3x^2-12

Solution for 3(x+2)(x-2)=3x^2-12 equation:

3(x+2)(x-2)=3x^2-12

We move all terms to the left:

3(x+2)(x-2)-(3x^2-12)=0

We use the square of the difference formula

x^2-(3x^2-12)-4=0

We get rid of parentheses

x^2-3x^2+12-4=0

We add all the numbers together, and all the variables

-2x^2+8=0

a = -2; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·(-2)·8
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*-2}=\frac{-8}{-4}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*-2}=\frac{8}{-4}
=-2
$